Final answer:
Placing a cell in a 10.0M glucose solution when it contains a 1.0M glucose concentration would result in water efflux due to the solution being hypertonic. If glucose concentrations were equal, there would be no net flow. Red blood cells in pure water would likely undergo hemolysis.
Step-by-step explanation:
If you place a cell that has a 1.0M solution of glucose in a beaker of 10.0M glucose, the cell will experience water efflux. This is because the beaker has a hypertonic solution relative to the cell's internal environment. The higher concentration of glucose outside the cell means that water will move out of the cell to balance the concentration of the solutes on both sides of the cell membrane. This process is driven by osmosis, which is the diffusion of water across a semipermeable membrane from an area of lower solute concentration to an area of higher solute concentration.
If the concentration of glucose was equal inside and outside of the cell, there would be no net flow of glucose across the cell membrane, because the concentration gradient, which drives passive transport, would not exist. The cell would be in an isotonic environment, where water influx and efflux are balanced, and the cell maintains its volume.
In an experiment with red blood cells placed in an environment of pure water, the cells would undergo hemolysis. This is because water would rush into the red blood cells due to the higher solute concentration inside them, causing the cells to swell and potentially burst. While most cells have mechanisms to prevent excessive water uptake, red blood cells lack these controls, making them prone to hemolysis in hypotonic environments where the solution has a lower solute concentration relative to the inside of the cells.