Final answer:
The mass of cerussite (PbCO₃) that contains 35g of lead is approximately 45.63 g, using molar mass and stoichiometry calculations.
Step-by-step explanation:
The question is asking to calculate the mass of cerussite (PbCO₃) that would contain 35g of lead (Pb). To find the answer, we need to use the concept of molar mass and stoichiometry. The molar mass of PbCO₃ is the sum of the molar masses of Pb, C, and 3 O atoms, which is 207 + 12 + (3 × 16) = 267 g/mol.
Knowing that 1 mole of PbCO₃ contains 1 mole of Pb, which is 207g of Pb, we can set up a proportion: (35g Pb / 207g Pb/mol) × (267 g PbCO₃/mol). The calculation gives us an answer of approximately 45.63 g of PbCO₃, which is not listed in the given options, suggesting that there may have been a typo or an error in the question.