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Formalize the following arguments and verify whether they are valid: a) The system is in a multi-user state if and only if it is operating normally. If the system is operating normally, the kernel is functioning. Either the kernel is not functioning or the system is in interrupt mode. If the system is not in multi-user state, then it is in interrupt mode. Thus, the system is not in interrupt mode.​

User Tingiskhan
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Final answer:

The argument is formalized using symbolic logic, with M, O, K, and I representing different states of the system. The conclusion that the system is not in interrupt mode (¬I) logically follows from the premises, making the argument valid.

Step-by-step explanation:

To formalize the given arguments, we will start by assigning the following symbolic representations to the statements:

  • M stands for 'The system is in a multi-user state.'
  • O stands for 'The system is operating normally.'
  • K stands for 'The kernel is functioning.'
  • I stands for 'The system is in interrupt mode.'

The original statements can now be formalized as follows:

  1. M ↔ O (The system is in a multi-user state if and only if it is operating normally.)
  2. O → K (If the system is operating normally, the kernel is functioning.)
  3. ¬K ∨ I (Either the kernel is not functioning or the system is in interrupt mode.)
  4. ¬M → I (If the system is not in multi-user state, then it is in interrupt mode.)

From the propositions given, we can check the validity of the conclusion that the system is not in interrupt mode (¬I).

To verify the validity of the argument, we will determine if the conclusion ¬I necessarily follows from the premises. Here, we can use a method such as truth tables or rules of inference to determine if the argument is valid.

Starting with the first premise M ↔ O, we know if M is true, then O must be true and vice-versa. Since O → K, if O is true, K must also be true. Given that ¬K ∨ I, but we already know from the previous premises that K is true, I must be false to satisfy this disjunction—hence the system cannot be in interrupt mode. Furthermore, since ¬M → I and we concluded I is false, M must be true to make this conditional true. Therefore, the argument is valid because the conclusion logically follows from the premises.

User Stanimir Yakimov
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