Question

A cylinder with a moveable piston contains 0.872 mol of neon gas and has a volume of 512 mL. What will its volume be in liters if an additional 0.329 mol of neon is added?

a) 1.46 L
b) 0.512 L
c) 1.84 L
d) 0.841 L

Answer 1

The volume of the cylinder will be approximately 0.989 L when 0.329 mol of neon is added.

Step-by-step explanation:

To solve this problem, we can use the concept of the ideal gas law. According to the ideal gas law, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature. Since the pressure and temperature are held constant, we can simplify the equation to V = nR/P.

In this case, we have an initial volume of 512 mL, which is equal to 0.512 L, and 0.872 mol of neon. When an additional 0.329 mol of neon is added, the total number of moles becomes 0.872 + 0.329 = 1.201 mol. Plugging these values into the equation, we get V = (1.201 mol)(0.0821 L·atm/mol·K)/(1 atm) = 0.989 L.

Therefore, the volume will be approximately 0.989 L when 0.329 mol of neon is added.