Final answer:
To calculate the molarity of the H2SO4 solution in titration, we first calculate the moles of NaHCO3 from its mass and molar mass, then its concentration in the diluted solution, and finally the moles of NaHCO3 used in the titration. Since the mole ratio of NaHCO3 to H2SO4 is 1:1, these moles also equal the moles of H2SO4 that reacted. The molarity of H2SO4 is then found by dividing these moles by the volume of the H2SO4 solution used, but an exact answer requires the specific value of X.
Step-by-step explanation:
To calculate the molar concentration of an H2SO4 solution in titration, first, we need the balanced chemical equation. The reaction of sodium bicarbonate (NaHCO3) with sulfuric acid (H2SO4) is represented as:
NaHCO3 (aq) + H2SO4 (aq) → NaHSO4 (aq) + CO2 (g) + H2O (l)
From this equation, it can be seen that 1 mole of H2SO4 reacts with 1 mole of NaHCO3. Using the information given, we can calculate the moles of NaHCO3 in the diluted solution first.
The mass of NaHCO3 is 3.3214 g and its molar mass is approximately 84 g/mol. Therefore, the initial moles of NaHCO3 are:
moles of NaHCO3 = mass (g) / molar mass (g/mol)
= 3.3214 g / 84 g/mol
= 0.03954 moles
This amount was diluted to 250.00 mL, so the concentration of the NaHCO3 solution is:
concentration = moles / volume (L)
= 0.03954 moles / 0.250 L
= 0.15816 M
Now we can calculate the moles of NaHCO3 used in the titration. Since 29.550X mL of the solution was used:
moles of NaHCO3 in titration = concentration * volume (L)
= 0.15816 M * (29.550X / 1000)
= 0.0046718X moles
Because the ratio of NaHCO3 to H2SO4 is 1:1, this is also the moles of H2SO4 reacted. Finally, we calculate the molarity of the H2SO4 solution:
molarity H2SO4 = moles of H2SO4 / volume (L)
= 0.0046718X moles / (25.00 / 1000) L
= 0.0046718X / 0.025
= 0.186872X M
We need the exact value of X to calculate the molarity of the H2SO4 solution accurately.