Final answer:
To find values of a quadratic function f(x)=5x^2+4x−5 for specific x-values, plug the x-values into the function. However, the student's provided answers for f(2) and f(−3) are incorrect; f(2) should be 23 and f(−3) should be 28. Without the specific value for 'a', we cannot determine f(4a).
Step-by-step explanation:
The student's question is about finding the values of a quadratic function for given x-values. The function in question is f(x)=5x^2+4x−5. To find the value of f(x) for a specific x-value, we simply substitute the given x-value into the function and solve.
- For f(0), substitute x = 0 into the function: f(0)=5(0)^2+4(0)−5 = −5.
- For f(2), substitute x = 2 into the function: f(2)=5(2)^2+4(2)−5 = 20+8−5 = 23.
- For f(−3), substitute x = −3 into the function: f(−3)=5(−3)^2+4(−3)−5 = 45−12−5 = 28.
- For f(4a), we cannot determine the value without a specific value for a.
Note that the values provided by the student in (a), (b), and (c) are not all correct based on the function provided.