Question

What is the bed slope of a trapezoidal canal with a discharge of 70 m^3/sec, bed width of 5m, uniform flow depth of 3 mm, and side slope of 2H:1V?

a. 0.0025
b. 0.005
c. 0.01
d. 0.02

Answer 1

The bed slope of a trapezoidal canal can be calculated using the Manning's equation, which relates the flow rate, cross-sectional area, hydraulic radius, and slope of the channel.

Step-by-step explanation:

The question asks for the bed slope of a trapezoidal canal given a set of parameters including discharge, bed width, flow depth, and side slope. This is a hydraulics problem that involves the application of the Manning equation for open channel flow to determine the slope. The bed slope of a trapezoidal canal can be calculated using the Manning's equation, which relates the flow rate, cross-sectional area, hydraulic radius, and slope of the channel. To calculate the bed slope, we can use the formula:

Slope = (Flow rate / (Bed width * uniform flow depth * side slope)

Slope = (70 m³/s) / (5m * 0.003m * 2)

Slope = 70 / 0.03 = 0.0025

Therefore, the bed slope of the trapezoidal canal is 0.0025 or 0.25%.