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A batter hits a baseball. The balls height (in feet) above the ground t seconds after it is hit is given by equation h= 16t2 + 80t +3. Find the height of the ball 4 seconds after it is hit.

a) 331 feet
b) 403 feet
c) 475 feet
d) 547 feet

1 Answer

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Final answer:

The height of the baseball 4 seconds after being hit is calculated using the equation h = 16t^2 + 80t + 3. Plugging in t = 4 seconds, the height is found to be 579 feet, which does not match any of the provided options. There may be a typo in the question or the options given.

Step-by-step explanation:

To find the height of the ball 4 seconds after it is hit, we use the given equation h = 16t^2 + 80t + 3. Substituting t = 4 seconds into the equation gives us:

h = 16(4)^2 + 80(4) + 3

h = 16(16) + 320 + 3

h = 256 + 320 + 3

h = 579 feet

Therefore, the height of the ball after 4 seconds is 579 feet. However, this answer is not included among the provided options (a) 331 feet, (b) 403 feet, (c) 475 feet, (d) 547 feet. The question may contain a typo in the equation, or in the given options, as none of the choices match the calculated result.

User Lord Farquaad
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