Question

In triangle ABC, where a = 3.4, c = 5.1, and B = 64°, solve for angles A and C, and side b. Round angles to the nearest tenth of a degree.

a) A = 28.2°, C = 87.8°, b = 4.7
b) A = 47.6°, C = 68.2°, b = 3.1
c) A = 61.8°, C = 33.2°, b = 2.8
d) A = 72.4°, C = 17.6°, b = 1.9

Answer 1

To solve for angles A and C, and side b in triangle ABC, use the Law of Sines.

Step-by-step explanation:

To solve for angles A and C, and side b in triangle ABC, we can use the Law of Sines. The Law of Sines states that for any triangle, the ratio of the length of a side to the sine of its opposite angle is constant. sin(A) / a = sin(B) / b = sin(C) / c

Given that a = 3.4, c = 5.1, and B = 64°, we can substitute these values into the Law of Sines equation. Solving for A and C, and using the formula for b, we get:

A = 28.2°, C = 87.8°, b = 4.7