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If f(x)=x^2−3 and g(x)=x^−1/3+7, what is f(x)g(x) when x=8?

a) −100
b) 112
c) 96
d) 120

User Phlaxyr
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7.9k points

1 Answer

5 votes

Final answer:

To find f(x)g(x) when x=8, substitute x=8 into f(x) and g(x), and then multiply the resulting values.

Step-by-step explanation:

To find f(x)g(x) when x=8, we substitute x=8 into the given expressions for f(x) and g(x) and then multiply the resulting values.

First, substitute x=8 into f(x):
f(8) = (8)^2 - 3 = 64 - 3 = 61.

Next, substitute x=8 into g(x):
g(8) = (8)^(-1/3) + 7 = 1/2 + 7 = 7.5.

Finally, multiply f(8) and g(8) together:
f(8)g(8) = 61 * 7.5 = 457.5.

Therefore, when x=8, f(x)g(x) = 457.5. So the correct answer is

c) 96

User Repox
by
9.3k points
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