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ABCF is a square with a side length of 14 cm. Given that DF = DC and E is the Center of the square, What is the area of the unshaded part of the figure?

a) 98−1/4 π
b) 98−1/2π
c) 98−π
d) 98−2π

User Senthuran
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1 Answer

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Final answer:

The area of the unshaded part of the square ABCF, which consists of a square and a semicircular shaded region, is 98 - 1/2π cm². The calculation involves finding the area of half of the square and then subtracting the area of the semicircle.

Step-by-step explanation:

To find the area of the unshaded part of the figure in the geometry problem pertaining to the square ABCF with a side length of 14 cm, we'll start by calculating the area of the square:

Area of a square = side × side = 14 cm × 14 cm = 196 cm².

Since point E is the center of the square, DE is equal to half the length of the side of the square, which is 7 cm. DF and DC are equal, forming two congruent right-angle triangles, DEF and DEC. Hence, triangle DEF is half of the square whose area is 98 cm².

The shaded region is a semicircle with radius 7 cm. The area of a semicircle is given by (1/2) π r², substituting the radius (7 cm) we get:

Area of a semicircle = 1/2 × π × 7 cm × 7 cm
= 1/2 × π × 49 cm²
= (1/2) × 49π cm²
= 24.5π cm².

Subtract the area of the semicircle from the area of half of the square to get the area of the unshaded part:

Area of the unshaded part = 98 cm² - 24.5π cm²
= 98 cm² - (1/2)π×49 cm²
= 98 - (1/2)π cm².

Thus, the correct answer is (b) 98 - 1/2π.

User Tara
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