159k views
2 votes
How many atoms of Be and S would be required to form a neutral ionic compound?

a) 1 Be atom and 1 S atom
b) 2 Be atoms and 1 S atom
c) 2 Be atoms and 2 S atoms
d) 1 Be atom and 2 S atoms

User Picchiolu
by
9.1k points

1 Answer

6 votes

Final answer:

To form a neutral ionic compound, 1 beryllium atom (Be²+) and 1 sulfur atom (S²-) are required as they will combine in a one-to-one ratio to balance each other's charges.

Step-by-step explanation:

The student asks about the number of beryllium (Be) and sulfur (S) atoms required to form a neutral ionic compound. Beryllium has an electron configuration of 1s²2s², which means it tends to lose two electrons to achieve a stable configuration, forming a Be²+ ion. Sulfur tends to gain two electrons to complete its valence shell, forming an S²- ion. Therefore, one Be²+ ion can balance out one S²- ion. The correct answer is that it would require 1 Be atom and 1 S atom to form a neutral ionic compound, which aligns with option (a).

User Andrey Subbotin
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.