Final answer:
The probability of a subscriber spending at least 1 hour reading The Wall Street Journal is found by calculating a Z-score and using the standard normal distribution table. The Z-score for 60 minutes is 0.6875, and the corresponding probability is 0.2546. The correct answer is 1 - 0.2546, which is 0.7454, and this is not listed in the provided options.
Step-by-step explanation:
The probability that a subscriber will spend at least 1 hour (or 60 minutes) reading The Wall Street Journal can be found using the Z-score formula, which is Z = (X - μ) / σ, where X is the value for which we want to find the probability, μ is the mean, and σ is the standard deviation.
The mean time spent (μ) is given as 49 minutes, and the standard deviation (σ) is 16 minutes. To find the probability for at least 1 hour, we need to calculate the Z-score for 60 minutes.
Z = (60 - 49) / 16 = 11 / 16 = 0.6875
Using the standard normal distribution table, we look up the probability for Z = 0.6875, which gives us a probability of 0.2546. However, since we want the probability of spending at least 1 hour, we need to subtract this value from 1 (as the table gives us the probability of being less than a certain value).
The correct probability is 1 - 0.2546 = 0.7454.
This is not one of the options provided, so it seems there may have been an error in the listed choices or the calculation process.