Question

Chase was trying to solve for x and y. He knows that the value of x is 3 × the value of y and that half of x plus twice y is equivalent to −14.

Which system of equations could he use to solve for x and y?

a) 3y=x; 12x+2y=−14
b) 3x=y; 12y+2x=−14
c) 3y+x=−14; 12x=2y
d) 3x+y=−14; 12y=2x

Answer 1

Chase can use the system of equations: 3x = y and 12y + 2x = -14 to solve for x and y.

Step-by-step explanation:

Chase can use the system of equations: 3x = y and 12y + 2x = -14 to solve for x and y.

First, we know that x is 3 times y, so we can rewrite the first equation as x = 3y. Substituting this into the second equation, we get 12y + 2(3y) = -14. Simplifying, we get 12y + 6y = -14, which gives us 18y = -14.

Solving for y, we divide both sides by 18 and get y = -14/18. Simplifying this gives us y = -7/9. Plugging this back into the first equation, we get x = 3(-7/9) which simplifies to x = -21/9 or x = -7/3.