Question

In the xy-plane, the graph of which of the following linear equations is perpendicular to the graph of the linear equation 3x-4y=0?

a. y = 4/3x
b. y = 3/4x
c. y = -4/3x
d. y = -3/4x

Answer 1

The linear equation that is perpendicular to the graph of 3x-4y=0 is y = -4/3x.The correct option is C.

Step-by-step explanation:

To determine which linear equation is perpendicular to the graph of the equation 3x-4y=0, we need to find the negative reciprocal of the slope of the given equation, which is 3/4. The slope of a line perpendicular to a given line is the negative reciprocal of the slope of the given line.

Therefore, the linear equation that is perpendicular to the graph of 3x-4y=0 is y = -4/3x (option c).