Final answer:
Using Henry's law, the new solubility is calculated by multiplying the original solubility by the ratio of the new pressure to the original pressure. In this case, the solubility at 120.0 kPa is calculated to be 3.192 g/L, which is not among the provided options.
Step-by-step explanation:
The original question asks about how much of a substance will dissolve in water at a higher pressure given its solubility at a lower pressure. This is a direct application of Henry's law, which states that the solubility of a gas in a liquid is directly proportional to the pressure of that gas above the liquid, as long as the temperature remains constant. The formula for Henry's law can be expressed as:
S1/P1 = S2/P2, where S1 is the original solubility, P1 is the original pressure, S2 is the new solubility, and P2 is the new pressure.
In this case:
- Original solubility (S1) = 0.80 g/L
- Original pressure (P1) = 30.1 kPa
- New pressure (P2) = 120.0 kPa
We are asked to find the new solubility (S2). So, we rearrange the equation to solve for S2:
S2 = S1 * P2 / P1
S2 = 0.80 g/L * 120.0 kPa / 30.1 kPa
S2 = 0.80 g/L * 3.99
S2 = 3.192 g/L
Thus, the solubility at 120.0 kPa is substantially more than at 30.1 kPa, and none of the provided options (a, b, c, d) match this value.