Question

How much heat is required to raise the temperature of 0.25 kg of water from 20°C to 30°C?

(A) 2.87 x 10³ J
(B) 1.05 x 10⁴ J
(C) 2.23 x 10⁵ J
(D) 1.76 x 10⁶ J

Answer 1

To calculate the heat required, use the specific heat capacity formula with the mass of water, specific heat of water, and the temperature change. The answer is approximately 1.05 x 10⁴ J, which corresponds to option (B).

Step-by-step explanation:

To calculate the heat required to raise the temperature of 0.25 kg of water from 20°C to 30°C, we use the specific heat capacity formula: q = mcΔT, where 'q' is the heat in joules, 'm' is the mass in kilograms (converted to grams), 'c' is the specific heat capacity, and 'ΔT' is the change in temperature in degrees Celsius.

Given that the specific heat of water is 4.184 J/g °C, the mass of the water is 0.25 kg (250 g), and the temperature change (ΔT) is 10°C (30°C - 20°C), we plug these values into the formula:

q = (250 g) × (4.184 J/g °C) × (10 °C)

q = 10,460 J, which is approximately 1.05 x 10⁴ J.

Therefore, the correct answer is (B) 1.05 x 10⁴ J.