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A new Outdoor Recreation is being built in Pagosa Springs. The perimeter of the rectangular playing field is 270 yards. The length of the field is 9 yards less than double the width. What are the dimensions of the playing field?

The width is __ yards.
The length is __ yards.

1 Answer

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Final answer:

The width of the playing field is 48 yards and the length is 87 yards.

Step-by-step explanation:

Let's let the width of the field be represented by 'w'.

The length of the field is 9 yards less than double the width, so it can be represented as '2w - 9'.

The perimeter of a rectangle is given by the formula P = 2(l + w), where l is the length and w is the width.

Given that the perimeter of the field is 270 yards, we can write the equation as 270 = 2((2w - 9) + w).

Simplifying the equation, we have 270 = 2(3w - 9), which becomes 270 = 6w - 18 when we distribute 2.

Adding 18 to both sides of the equation, we get 288 = 6w.

Dividing both sides of the equation by 6, we find that w = 48.

So, the width of the playing field is 48 yards.

To find the length, we substitute the value of w back into the equation for the length: l = 2(48) - 9 = 87.

Therefore, the dimensions of the playing field are: Width = 48 yards, Length = 87 yards.

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