Question

What will be the concentration of H2SO4 using the following data: 10 cm³ of the solution required 19.80 cm³ of 0.01 NaoH for the neutralization?

A. 0.0099 mol/L
B. 0.0198 mol/L
C. 0.099 mol/L
D. 0.198 mol/L

Answer 1

The concentration of H₂SO₄ is calculated by using the volume of NaOH titrated and its normality to find the moles of NaOH, dividing by 2 to get moles of H₂SO₄, and then dividing by volume of H₂SO₄ solution in liters. The correct concentration is 0.0099 mol/L.

Step-by-step explanation:

We are given that 19.80 cm³ of 0.01 N NaOH is required to neutralize 10 cm³ of H₂SO₄ solution. To calculate the concentration of H₂SO₄, we use the equation from the concept of titration that states the number of moles of acid is equal to the number of moles of base in the neutralization reaction. Since NaOH and H₂SO₄ react in a 2:1 ratio, we need to divide the number of moles of NaOH by 2 to get the moles of H₂SO₄.

First, we calculate the moles of NaOH:

1. Moles of NaOH = (Volume in liters) x (Normality)
2. Moles of NaOH = (19.80 cm³ x 10⁻³ L/cm³) x 0.01 N
3. Moles of NaOH = 0.000198 x 1
4. Moles of NaOH = 0.000198 moles

Now, to get the moles of H₂SO₄:

1. Moles of H₂SO₄ = 0.000198 moles NaOH / 2
2. Moles of H₂SO₄ = 0.000099 moles

Finally, we can calculate the concentration:

1. Concentration of H₂SO₄ = moles of H₂SO₄ / volume in liters
2. Concentration of H₂SO₄ = 0.000099 moles / 0.010 L
3. Concentration of H₂SO₄ = 0.0099 M or mol/L

Therefore, the correct answer is A. 0.0099 mol/L.