Question

Ling is making snack bags for the class trip to the museum. To fill the bags, she has 48 cereal bars, 72 boxes of raisins, and 24 bottles of water. What is the greatest number of snack bags Ling can make if she wants to use all of the items and have the same number of each item in each bag? How many of each item will be in a bag?

A: 8 snack bags, 9 boxes of raisins, 6 cereal bars, and 2 bottles of water in each bag
B: 12 snack bags, 6 boxes of raisins, 4 cereal bars, and 2 bottles of water in each bag
C: 6 snack bags, 8 boxes of raisins, 12 cereal bars, and 3 bottles of water in each bag
D: 10 snack bags, 7 boxes of raisins, 5 cereal bars, and 3 bottles of water in each bag

Answer 1

Ling can make 24 snack bags with each bag containing 2 cereal bars, 3 boxes of raisins, and 1 bottle of water. The options provided in the question do not present the correct combination based on the items Ling has.

Step-by-step explanation:

To determine the greatest number of snack bags Ling can make using all of the items and having the same number of each item in each bag, we need to find the greatest common divisor (GCD) of the number of cereal bars, boxes of raisins, and bottles of water.

Ling has 48 cereal bars, 72 boxes of raisins, and 24 bottles of water. The GCD of 48, 72, and 24 is 24. Therefore, she can make the greatest number of snack bags by dividing all the items by 24.

When we divide each item by 24, we find:

• Cereal bars: 48 ÷ 24 = 2 cereal bars per bag
• Boxes of raisins: 72 ÷ 24 = 3 boxes of raisins per bag
• Bottles of water: 24 ÷ 24 = 1 bottle of water per bag

Therefore, the answer is that Ling can make 24 snack bags, with each bag containing 2 cereal bars, 3 boxes of raisins, and 1 bottle of water. None of the options A, B, C, or D is correct.