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If (z)^2 is directly proportional to ( w ) and ( z = 4 ) when ( w = 8 ), what is the value of ( z ) when ( w = 16 )?

A. ( 2 )
B. ( 4 )
C. ( 8 )
D. ( 16 )

User Cullen
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1 Answer

3 votes

Final answer:

By using the concept of direct proportionality and the given z value when w equals 8, the constant of proportionality (k) can be found. With k calculated, the z value corresponding to w equaling 16 can be determined. Integer assumptions lead to z equaling 8 being the most plausible answer.

Step-by-step explanation:

To solve this problem, we will use the concept of direct proportionality. If (z)^2 is directly proportional to (w), we can write it as (z)^2 = k * w, where k is the constant of proportionality. Given that (z = 4) when (w = 8), we first find the value of k: 4^2 = k * 8

This simplifies to 16 = 8k, so k = 2. Now that we have the constant, we can find the value of (z) when (w = 16):

(z)^2 = 2 * 16

(z)^2 = 32

z = √32

z = √(16 * 2)

Since √16 is 4, z = 4√2. However, in the answer choices given, no such option exists, indicating a possible typo in the question or choices. Assuming the choices are meant to represent integer values of z, we should expect the value of z to increase as w has doubled (8 to 16), so logically the answer should be greater than 4 (the z-value when w was 8). The correct answer assuming integer values would be (C) z = 8, as it's the next integer that is a factor of 32 and greater than 4.

User Augustomen
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