Final answer:
The farmer should buy 20 bags of mixture A and 88 bags of mixture B to obtain the required fertilizer at minimum cost.
Step-by-step explanation:
To find the minimum cost of obtaining the required fertilizer, we need to determine the number of bags of each type that the farmer should buy. Let's assume the farmer buys x bags of mixture A and y bags of mixture B.
To find the minimum cost of obtaining the required fertilizer, we need to determine the number of bags of each type that the farmer should buy. Let's assume the farmer buys x bags of mixture A and y bags of mixture B.
From the given information, we can set up the following equations:
- 20x + 50y = 4800 (equation for phosphate)
- 80x + 50y = 7200 (equation for nitrogen)
Solving the two equations simultaneously, we can find the values of x and y. Multiplying the first equation by 8 and subtracting it from the second equation, we get:
Simplifying this equation, we find: -120x = -2400. Dividing by -120 on both sides: x = 20.
Substituting the value of x in the first equation, we find: 20(20) + 50y = 4800. Simplifying: 400 + 50y = 4800. Subtracting 400 from both sides: 50y = 4400. Dividing by 50 on both sides: y = 88.
Therefore, the farmer should buy 20 bags of mixture A and 88 bags of mixture B in order to obtain the required fertilizer at minimum cost.