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What is the molality of a solution prepared by dissolving 0.114 mole of chloroform in 476 g of toluene?

User Kinya
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Final answer:

The molality of the solution prepared by dissolving 0.114 mole of chloroform in 476 g of toluene is 0.239 m.

Step-by-step explanation:

The molality of a solution is calculated by the number of moles of solute per kilogram of solvent. To find the molality of a chloroform solution in toluene, we use the given amounts: 0.114 moles of chloroform dissolved in 476 grams (or 0.476 kg) of toluene.

Molality (m) = moles of solute / kilograms of solvent
= 0.114 moles / 0.476 kg
= 0.239 mol/kg (or 0.239 m)

This means the molality of the chloroform solution in toluene is 0.239 m.

User Michael Glukhovsky
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