Question

A car starting from rest accelerates at the rate of (5 m/s^2) until it attains a speed of (30 m/s). Over what distance was this acceleration accomplished?

a. (90 m)
b. (120 m)
c. (150 m)
d. (180 m)

Answer 1

The car accelerated from rest to 30 m/s with an acceleration of 5 m/s^2 over a distance of 90 meters.

Step-by-step explanation:

When a car accelerates from rest to a speed of 30 m/s with an acceleration of 5 m/s2, we can use the kinematic equation to find the distance covered during this acceleration:

s = (v2 - u2) / (2a)

Where:

• s = distance covered
• v = final velocity (30 m/s)
• u = initial velocity (0 m/s)
• a = acceleration (5 m/s2)

Plugging the values into the equation:

s = (302 - 02) / (2 × 5)

s = (900) / (10)

s = 90 m

Therefore, the acceleration was accomplished over a distance of 90 meters (Option a).