Question

Solve the equation (1R_p = 15.5omega + 18.2omega) for (R_p).

A. R_p = 1/15.5omega + 18.2omega
B. R_p = 1/5.5omega - 18.2omega
C. R_p = 5.5omega + 8.2omega
D. R_p = 5.5omega ⋅ 8.2omega5.5omega + 8.2omega

Answer 1

To solve the equation (1/Rp = 15.5ω + 18.2ω) for Rp, we need to isolate Rp on one side of the equation. The correct solution is Rp = 1 / (1/15.5ω - 18.2ω).

Step-by-step explanation:

To solve the equation (1/Rp = 15.5ω + 18.2ω) for Rp, we need to isolate Rp on one side of the equation.

We can start by subtracting 18.2ω from both sides of the equation:

1/Rp - 18.2ω = 15.5ω

Then, we can take the reciprocal of both sides:

Rp = 1 / (1/Rp - 18.2ω)

Therefore, the correct solution is Rp = 1 / (1/15.5ω - 18.2ω).