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Input Voltage = 220V, Input Current = 1 A. The transformer is expected to work with 90% efficiency and expected to get 12V 5A output. If the primary coil consists of 2000 turns with 22 AWG copper wire, how many turns are required to be wound in the secondary coil?

a) 500 turns

b) 550 turns

c) 600 turns

d) 650 turns

1 Answer

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Final answer:

To calculate the number of turns required in the secondary coil, we can use the formula Np/Ns = Vp/Vs. In this case, with a primary coil of 2000 turns and an input voltage of 220V, the number of turns required in the secondary coil is approximately 109 turns.

Step-by-step explanation:

To calculate the number of turns required in the secondary coil, we can use the formula:

Np/Ns = Vp/Vs

Where Np is the number of turns in the primary coil, Ns is the number of turns in the secondary coil, Vp is the input voltage, and Vs is the output voltage.

In this case, the primary coil consists of 2000 turns and the input voltage is 220V. The desired output voltage is 12V. Plugging these values into the formula, we can solve for Ns:

Np/Ns = 220V/12V

2000/Ns = 18.33

Ns = 2000/18.33

Ns ≈ 109.02

Rounded to the nearest whole number, the number of turns required in the secondary coil is approximately 109 turns.

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