Answer:
10.4 to nearest tenth.
Explanation:
If we draw lines from the centre of the circle to each vertex of the hexagon we get 6 equilateral triangles of side length 2.
Altitude of each triangle = sqrt(2^2 - 1^2)
= sqrt3.
So the area of 1 triangle = 1/2 * 2 * sqrt3
= sqrt3
Therefore the area of the hexagon = 6 * sqrt3
= 6sqrt3
= 10.3923