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A 24 W LED bulb requires 22 V to operate. What is its resistance?

a) R = 0.917 Ω
b) R = 1.091 Ω
c) R = 1.286 Ω
d) R = 1.524 Ω

1 Answer

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Final answer:

The resistance of the 24W LED bulb operating at 22V is approximately 1.091Ω.

Step-by-step explanation:

The resistance of the LED bulb can be calculated using Ohm's Law, which states that the resistance is equal to the voltage divided by the current. In this case, the power of the bulb is given as 24W, and the voltage is given as 22V. To find the current, we can use the equation power = voltage multiplied by current. Therefore, 24W = 22V multiplied by current. Rearranging the equation to find the current, we get current = power divided by voltage. Substituting the given values, we get current = 24W divided by 22V, which is approximately 1.091A. Now, we can find the resistance by using Ohm's Law. Resistance = voltage divided by current. Substituting the given values, we get resistance = 22V divided by 1.091A, which is approximately 20.13Ω. Therefore, the correct answer is option b) R = 1.091Ω.

User John Erck
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