Question

The equation of a transverse sinusoidal wave is given by y=2×10-³sin(18x−600+30∘). Find the amplitude of the wave.

a) 2×10−³
b) 18
c) 600
d) 30∘

Answer 1

The amplitude of the provided sinusoidal wave equation y=2×10⁻³ sin(18x−600+30°) is 2×10⁻³, which is letter option (a).

Step-by-step explanation:

The amplitude of a sinusoidal wave can be determined from its equation, which generally has the form y = A sin(kx - ωt + φ), where A represents the amplitude, k is the wave number, ω is the angular frequency, and φ is the phase constant.

In the given sinusoidal wave equation, y=2×10⁻³ sin(18x−600+30°), the amplitude is the coefficient before the sine function, which is 2×10⁻³.

Therefore, the correct answer is (a) 2×10⁻³.