Question

Monty has to make his own dinner. He chooses 1 vegetable, 1 meat, and 1 drink. He has 3 vegetables to choose from, 3 meats, and 2 drinks. How many different dinner combinations can there be?

a) 6 combinations
b) 9 combinations
c) 18 combinations
d) 12 combinations

Answer 1

By multiplying the number of options for each category—3 vegetables, 3 meats, and 2 drinks—Monty can make 18 different dinner combinations.

Step-by-step explanation:

To find the total number of different dinner combinations Monty can make, we need to multiply the number of choices he has for each item. Monty has 3 choices of vegetables, 3 choices of meats, and 2 choices of drinks. Therefore, the total number of combinations is the product of these choices.

So, if we calculate the combinations, it is: 3 (vegetables) × 3 (meats) × 2 (drinks) = 18 different dinner combinations.

Monty has 3 vegetables, 3 meats, and 2 drinks to choose from for his dinner. To find the number of different dinner combinations, we multiply the number of choices for each category: 3 vegetables x 3 meats x 2 drinks = 18 combinations. Therefore, the correct answer is option c) 18 combinations.