Question

Two identical charges of magnitude 3.0 C lie 3.0 m apart. What is the magnitude of the electric force experienced by each charge if they are in vacuum?

a) 9.0 N
b) 27.0 N
c) 81.0 N
d) 243.0 N

Answer 1

The magnitude of the electric force experienced by each charge is 27.0 N.

Step-by-step explanation:

The magnitude of the electric force experienced by each charge can be calculated using Coulomb's law:

F = k * (q1 * q2) / r^2

Where:

F is the magnitude of the electric force

• k is the electrostatic constant (9 x 10^9 N*m^2/C^2)
• q1 and q2 are the magnitudes of the charges (3.0 C in this case)
• r is the distance between the charges (3.0 m in this case)

Plugging in the values, we get:

F = (9 x 10^9 N*m^2/C^2) * (3.0 C)^2 / (3.0 m)^2 = 27.0 N

Therefore, the magnitude of the electric force experienced by each charge is 27.0 N.