Question

Consider the equation y = ax^2 + bx + c.

(a) If y = c, what two values can x be?
a) -c/a, -c/b
b) -c/a, -b/c
c) -b/a, -c/a
d) -c/b, -a/b

Answer 1

If y = c, the values of x can be -b/a and 0 in the given equation y = ax^2 + bx + c.

Step-by-step explanation:

The given equation is y = ax^2 + bx + c. If y = c, we can substitute c for y in the equation and solve for x.

Substituting c for y, we get c = ax^2 +bx +c.

Next, we can rearrange the equation to solve for x: ax^2 +bx +c - c = 0, which simplifies to ax^2 +bx = 0.

Finally, we can factor out x from the equation to find the values of x: x(ax + b) = 0. So, the two values that x can be are -b/a and 0.