Question

Employees of Al’s superMart constantly reorganize and reshelve merchandise. In doing so, they calculate floor space needed for displays. The algebraic expression

L⋅W gives the floor space needed in square units for a display that measures length
L units and width W units. Calculate the floor space needed for a display whose length is 6.6 feet and whose width is 6 feet. Sq ft?

A. 39.6 sq ft

B. 39.0 sq ft

C. 36.6 sq ft

D. 22.0 sq ft

Answer 1

To find the area of a display at Al’s SuperMart, multiply its length by its width. In this case, 6.6 feet multiplied by 6 feet equals 39.6 square feet, which is the required floor space.

Step-by-step explanation:

To calculate the floor space needed for a display, you need to multiply the length by the width. The algebraic expression for the area of a rectangle is L · W, where L is the length and W is the width. For the given display, with a length of 6.6 feet and a width of 6 feet, the calculation would be:

Area = Length · Width = 6.6 feet · 6 feet

When you multiply 6.6 by 6, you get:

Area = 39.6 square feet

Therefore, the floor space needed for the display is 39.6 square feet.