Question

The city of Raleigh has 9500 registered voters. There are two candidates for city council in an upcoming election: Brown and Feliz. The day before the election, a telephone poll of 400 randomly selected registered voters was conducted. 164 said they'd vote for Brown, 211 said they'd vote for Feliz, and 25 were undecided.

Give the sample statistic for the proportion of voters surveyed who said they'd vote for Brown. Note: The proportion should be a fraction or decimal, not a percent.
This sample statistic suggests that we might expect ________ of the 9500 registered voters to vote for Brown.

a.0.41
b.0.54
c.0.38
d.0.25

Answer 1

The sample statistic for the proportion of voters who said they'd vote for Brown is 0.41. Multiplying this proportion by the total number of registered voters in Raleigh (9500), we can expect approximately 3895 registered voters to support Brown.

Step-by-step explanation:

The sample statistic for the proportion of voters surveyed who said they'd vote for Brown is calculated by dividing the number of people who said they would vote for Brown by the total number of people surveyed. In this case, it would be 164 (for Brown) divided by 400 (total surveyed), which gives us 0.41.

Now, to estimate the number of registered voters out of the 9500 who would vote for Brown, we multiply the total number of registered voters by the sample proportion. So, 9500 registered voters multiplied by 0.41 gives us 3895 voters. Hence, the answer is (a) 0.41, and we might expect that 3895 of the 9500 registered voters to vote for Brown.