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For the points

P(−21,2) and
Q(28,1), find the distance
d(P,Q) and the coordinates of the midpoint
M of the segment PQ.


a.d(P,Q)= √2402
b.d(P,Q)=49
c.d(P,Q)=7
d.d(P,Q)= √50
Midpoint Coordinates:

a.M=(3.5,1.5)
b.M=(−3,2)
c.M=(14,0)d.
M=(−21,1)

1 Answer

2 votes

Final answer:

The distance between points P(-21, 2) and Q(28, 1) is √2402, and the midpoint M of the segment PQ has coordinates (3.5, 1.5).

Step-by-step explanation:

To find the distance d(P, Q) between the two points P(-21, 2) and Q(28, 1), we use the distance formula:

d(P, Q) = √[(x2 - x1)^2 + (y2 - y1)^2]

d(P, Q) = √[(28 - (-21))^2 + (1 - 2)^2] = √[49^2 + (-1)^2] = √[2401 + 1] = √2402

The correct answer is a. d(P, Q) = √2402.

To find the Midpoint Coordinates M of the segment PQ, we use the midpoint formula:

M = ((x1 + x2)/2, (y1 + y2)/2)

M = ((-21 + 28)/2, (2 + 1)/2) = (7/2, 3/2) = (3.5, 1.5).

The correct coordinates for M are a. M=(3.5,1.5).

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