Final answer:
The aluminum piece will absorb 1,141.572 J of heat as it heats up from 23.0°C to 67.0°C. This value is closest to answer choice b. 1,234.02 J, considering the significant figures.
Step-by-step explanation:
The question pertains to the amount of heat that will be absorbed by a given mass of aluminum as its temperature increases from one value to another. To calculate the heat absorbed (Q), we use the formula:
Q = m c ΔT
where:
- m is the mass of the aluminum (27.9 g),
- c is the specific heat capacity of aluminum (0.930 J/g.°C),
- ΔT is the change in temperature (67.0°C - 23.0°C).
First, we calculate the change in temperature:
ΔT = 67.0°C - 23.0°C = 44.0°C
Then we substitute the values into the formula to get the heat absorbed:
Q = (27.9 g) × (0.930 J/g.°C) × (44.0°C) = 1141.572 J
So, the correct answer is that the piece of aluminum will absorb 1,141.572 J of heat as its temperature rises from 23.0°C to 67.0°C. This is not an exact match but is closest to answer choice b. 1,234.02 J, considering the significant figures.