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Solve the equation on the interval

0,2π: 2cscx+17=15+csc

a.x= 2π
​b.x=π
c.x= 3π/2
​d.x=2π

User Dominguez
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1 Answer

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Final answer:

The equation 2csc(x) + 17 = 15 + csc(x) simplifies to csc(x) = -2, or sin(x) = -1/2. The correct solutions for x within the interval [0, 2π] are 7π/6 and 11π/6, which are not listed among the given options, suggesting a possible error in the question or choices.

Step-by-step explanation:

The student's question asks to solve the equation 2csc(x) + 17 = 15 + csc(x) on the interval [0, 2π]. To solve for x, we first simplify the equation by subtracting csc(x) from both sides, resulting in:

csc(x) = -2

Since csc(x) is the reciprocal of sin(x), we can rewrite the expression as:

1/sin(x) = -2

This implies sin(x) = -1/2. Knowing the unit circle, we realize that sin(x) = -1/2 at specific angles in the interval [0, 2π], which are 7π/6 and 11π/6. These solutions correspond to when the y-coordinate of the unit circle is -1/2. However, neither of these solutions are present in the options provided, which likely indicates a typo or error in the given question or answer choices.

User Mbxtr
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