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A crystalline solid irradiated by a neutron beam, which has a wavelength of 2.567 Angstroms. An interlayer distance of 3.325 Angstrom will give an observed angle (20) of:

a) 17.26°
b) 45.41°
c) 34.530
d) 63.40

1 Answer

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Final answer:

The student's question is about applying Bragg's Law to find the diffraction angle in a crystal structure when a neutron beam is used. It requires knowledge of the neutron beam wavelength and the crystal's interlayer spacing to calculate the angle of the first-order diffraction peak.

Step-by-step explanation:

The question involves determining the observed angle (2θ) for diffraction in a crystalline solid when a neutron beam with a wavelength of 2.567 Angstroms is used, and the interlayer distance in the crystal is 3.325 Angstrom. This is a classic example of applying Bragg's Law, which is used in X-ray diffraction experiments to find the angles at which constructive interference of the reflected waves occurs, providing information about the crystal structure.

Bragg's Law is given by:

nλ = 2d sin(θ)

Where:

  • n is the order of the diffraction peak (n = 1 for first-order diffraction)
  • λ is the wavelength of the incident beam
  • d is the spacing between the planes in the crystal
  • θ is the angle between the incident ray and the planes in the crystal, and 2θ is the total diffraction angle observed

In this scenario, assuming first-order diffraction (n=1), the Bragg's Law equation becomes:

2.567 = 2 × 3.325 sin(θ)

By solving for θ, we can determine the angle 2θ that corresponds to the observed diffraction peak.

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