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You are building a 3-foottall dresser. You want the volume to be 42 cubic feet.a. What should the area of the base be?b. Give a possible length & width of the base.c. Make a hand drawn sketch of the dresser with the dimensions you chose.

User Ligaya
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1 Answer

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12 votes

Answer

a. 14 ft²

b. length = 7 ft, width = 2 ft

c.

Explanation

a. The dresser has a shape of a rectangular prism. Then, the volume of the dresser is calculated as follows:


V=\text{ Area of the base}\cdot\text{ height}

Substituting with V = 42 cubic ft, and height = 3 ft, and solving for the area of the base:


\begin{gathered} 42=\text{ Area of the base }\cdot3 \\ (42)/(3)=\text{ Area of the base} \\ 14\text{ ft}^2\text{ = Area of the base} \end{gathered}

b. The base of the dresser is a rectangle. Then, the area of the base is calculated as follows:


A=\text{ length}\cdot\text{ width}

Assuming the length is 7 ft, and substituting A = 14 sq ft, the width must be:


\begin{gathered} 14=7\cdot\text{ width} \\ (14)/(7)=\text{ width} \\ 2\text{ ft = width} \end{gathered}

You are building a 3-foottall dresser. You want the volume to be 42 cubic feet.a. What-example-1
User Redoy
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