Question

A 8.0 mL bubble of gas is released at the bottom of the ocean where the pressure is 685 kPa and the temperature is 12 C. Calculate the volume of the gas bubble when it reaches the surface of the water, where the pressure is 99 kPa and the temperature is 26 C.

Answer 1

To calculate the volume of the gas bubble when it reaches the surface of the water, we can use the combined gas law. By plugging in the given values and solving for the final volume, we find that it is 2.65 mL.

Step-by-step explanation:

To solve this problem, we can use the combined gas law, which states that the product of the initial pressure, volume, and temperature is equal to the product of the final pressure, volume, and temperature:

P1 * V1 / T1 = P2 * V2 / T2

First, we need to convert the temperatures from Celsius to Kelvin by adding 273:

T1 = 12 + 273 = 285 K

T2 = 26 + 273 = 299 K

Next, we can plug in the given values and calculate the final volume:

(685 kPa * 8.0 mL) / 285 K = (99 kPa * V2) / 299 K

Solving for V2, we get:

V2 = (99 kPa * 8.0 mL * 299 K) / (685 kPa * 285 K) = 2.65 mL

Therefore, the volume of the gas bubble when it reaches the surface of the water is 2.65 mL.