Final answer:
To determine if the sample mean is higher than 5.8 visits per year, a hypothesis test can be performed using the provided data.
Step-by-step explanation:
To determine if the sample mean is higher than 5.8 visits per year, we need to perform a hypothesis test. We will use a one-sample t-test since we have a sample mean and want to compare it to a population mean.
The null hypothesis, denoted as H0, assumes that the sample mean is not higher than 5.8 visits per year. The alternative hypothesis, denoted as H1, assumes that the sample mean is higher than 5.8 visits per year.
Using the provided data, we calculate the sample mean, standard deviation, and the t-statistic. We then compare the t-statistic to the critical value from the t-distribution table at a significance level of 0.05. If the t-statistic is greater than the critical value, we reject the null hypothesis and conclude that the sample mean is higher than 5.8 visits per year.