The question requires us to calculate the volume of 0.02 mol of neon gas under standard temperature and pressure conditions (STP).
Under STP, the volume of one mol of any gas corresponds to 22.4 liters of this gas. With that information, we can calculate the volume of 0.02 mol of neon gas as it follows:
1 mol of neon gas ---------- 22.4 L of neon gas
0.02 mol of neon gas ---- x
Then, solving for x, we have that 0.02 mol of neon gas corresponds to 0.448 liters under STP.