Question

Robert, D’aunte, Kalin and Jasir are members of the basketball team in charge of selling tickets. Student tickets to the Morehouse Basketball holiday tournament cost $15 for student tickets and $20 for adult tickets. The holiday tournament sold four hundred fifty tickets, totaling $7,500.00 in receipts. How many (of each) tickets were sold

Answer 1

To solve this problem, we set up a system of equations. We find that 300 student tickets and 150 adult tickets were sold.

Step-by-step explanation:

To solve this problem, we can set up a system of equations. Let's say x represents the number of student tickets sold and y represents the number of adult tickets sold.

We know that the total number of tickets sold is 450, so we can write the equation x + y = 450.

We also know that the total receipts from the ticket sales is $7,500, so we can write the equation 15x + 20y = 7500.

We now have a system of equations:

1. x + y = 450
2. 15x + 20y = 7500

To solve this system, we can use the method of substitution or elimination. Let's use substitution here.

From equation 1, we can isolate x by subtracting y from both sides: x = 450 - y.

Substituting this expression for x into equation 2, we get 15(450 - y) + 20y = 7500.

Simplifying the equation, we have 6750 - 15y + 20y = 7500.

Combining like terms, we get 5y = 750.

Dividing both sides by 5, we find that y = 150. Substituting this value into equation 1, we can find x: x + 150 = 450, so x = 300.

Therefore, 300 student tickets and 150 adult tickets were sold.