Question

when a unit positive charge is displaced at a distance 40cm towards point charge of magnitude 0.4mC then calculate absolute potential

Answer 1

The absolute potential near the surface of the point charge is 8.99 x 10^6 V.

Step-by-step explanation:

The potential near the surface of a point charge can be calculated using the formula:

V = kQ / r

Where V is the potential, k is the Coulomb's constant (8.99 x 10^9 Nm^2/C^2), Q is the magnitude of the point charge, and r is the distance from the point charge.

In this case, the magnitude of the point charge is 0.4 mC and the distance is 40 cm, which is 0.4 m. Plugging these values into the formula, we get:

V = (8.99 x 10^9 Nm^2/C^2 * 0.4 x 10^-3 C) / 0.4 m = 8.99 x 10^6 V

Therefore, the absolute potential near the surface of the point charge is 8.99 x 10^6 V.