Question

I solved the first one but I can’t figure out the second one

Answer 1

`\begin{gathered} (h\circ k)(3)=3 \\ (k\circ h)(-4b)=-4b \end{gathered}`

Step-by-step explanation:

We need to use the definition for a composition of functions and inverse functions.

If h and k are inverse functions:

`(k\circ h)(x)=(h\circ k)(x)=x`

Then, the composition of two inverse functions give us the input (x, in the definition above).

Thus:

`\begin{gathered} (h\circ k)(3)=3 \\ (k\circ h)(-4b)=-4b \end{gathered}`