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The voltage v(t)=350cos(ωt) volts is applied to a load consisting of a 15- Ω resistor in parallel with a capacitive reactance XC=20Ω.

Calculate the instantaneous power absorbed by the resistor

User Nitty
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Final answer:

To find the instantaneous power absorbed by the resistor, divide the voltage by the resistance to obtain the current. Use the equation p(t) = (350cos(ωt) / 15)^2 * 15 to find the power absorbed by the resistor.

Step-by-step explanation:

Since the voltage across the resistor is given by v(t) = 350cos(ωt), we can calculate the current through the resistor using Ohm's Law. The current, i(t), can be found by dividing the voltage by the resistance, i(t) = v(t)/R. Therefore, i(t) = 350cos(ωt) / 15.

The power absorbed by the resistor is given by the equation P = I^2 * R, where I is the rms current and R is the resistance. To find the instantaneous power absorbed by the resistor, we can use the equation p(t) = i(t)^2 * R. Substituting the value of i(t) obtained earlier, we get p(t) = (350cos(ωt) / 15)^2 * 15.

User Klors
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