Question

A 5-uF capacitor is charged to 1000 V. Determine the initial stored charge and energy. If this capacitor is discharged to 0 V in a time interval of 1 us, find the average power delivered by the capacitor during the discharge interval.

Answer 1

The initial stored charge in a 5-uF capacitor charged to 1000 V is 5 mC, and the energy stored is 2.5 Joules. During the 1 us discharge interval, the capacitor delivers an average power of 2.5 MW.

Step-by-step explanation:

To determine the initial stored charge and energy in a 5-uF capacitor charged to 1000 V, we use the formulas for charge (Q = C * V) and energy (E = 1/2 * C * V2). For the charge Q, we get Q = 5 x 10-6F * 1000 V = 5 x 10-3 C or 5 mC. The energy stored (E) in the capacitor would be E = 1/2 * 5 x 10-6F * (1000 V)2 = 2.5 Joules.

When the capacitor is discharged to 0 V in a time interval of 1 us, we can find the average power delivered using the formula for power (P = E/t). Thus, P = 2.5 J / 1 x 10-6 s = 2.5 x 106 W or 2.5 MW.

This entire process represents a discharge interval during which the capacitor releases its stored charge and energy.