Final answer:
The full-load current of the 3-phase induction motor is approximately 27.94 A.
Step-by-step explanation:
To calculate the full-load current of a 3-phase induction motor, you need to use the formula:
I = P / (sqrt(3) * V * PF)
where:
- I is the current
- P is the power output in watts (20kW = 20000W)
- V is the voltage (415V)
- PF is the power factor (assumed to be 1 for simplicity)
Substituting the values, we have:
I = 20000 / (sqrt(3) * 415 * 1) = 27.94 A
Therefore, the full-load current of the motor is approximately 27.94 A.