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For a negative-biased clamp circuit, what is VOUT(t), if VIN(t) = 2sin(ωt), VBIAS = 5 V, and Vf = 0.7V?

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Final answer:

The output voltage VOUT(t) for a negative-biased clamp circuit can be calculated using the formula VOUT(t) = VIN(t) - VBIAS - Vf, where VIN(t) is the input voltage, VBIAS is the bias voltage, and Vf is the forward voltage of the diode.

Step-by-step explanation:

The given circuit is a negative-biased clamp circuit. In this circuit, during the negative half-cycle of the input signal, the diode is forward biased, causing it to conduct. As a result, the output voltage will be the same as the input voltage.

Given that VIN(t) = 2sin(ωt), VBIAS = 5 V, and Vf = 0.7 V, we can calculate VOUT(t) using the following formula:

VOUT(t) = VIN(t) - VBIAS - Vf = 2sin(ωt) - 5 - 0.7 = 2sin(ωt) - 5.7 V

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