Final answer:
To determine the load shared by transformer A, calculate the magnitude of the impedances, find the reciprocal and then the sum of the reciprocals. Use this information to find the ratio of load that transformer A will carry compared to the total load.
Step-by-step explanation:
The student is asking about the load shared by two parallel single-phase transformers based on their impedances. Impedance of transformer A (Za) is given as (1+j6) ohms and that of transformer B (Zb) as (1.5+j1.5) ohms. The total apparent power (S) is given as 160 kW with a power factor of 0.80 lagging. The complex powers for transformers A and B can be found using the formula S = V2/Z where V is the voltage. However, the voltage is not provided, and it's typically the same for both transformers in parallel, thus we can ignore it in the computation of relative loads. The load shared by each transformer is inversely proportional to their respective impedances. First, we calculate the magnitude of the impedances: |Za| = √(12 + 62) and |Zb| = √(1.52 + 1.52). Next, we find the total impedance Zt which is 1/|Za| + 1/|Zb|. Following that, we determine the fraction of the total load each transformer will carry: Load on A (SA) = S * (1/|Za|) / Zt.
The ratio of the load that transformer A carries to the total load is the same as the ratio of the reciprocal of its impedance to the sum of the reciprocals of both impedances.